Algebra Problems, Math Problems

Problem of the Day: 2/27/13

Three positive integers have a product of 60. What is their smallest possible sum?

Solution to yesterday’s problem:

Let’s use the blanks method with probabilities for this problem. There are three blanks for three draws:

____ ____ ____

There are 12 possible marbles for the first draw, and 3 of them are green.

__3/12__ ____ ____

There are 11 possible marbles for the second draw (he has taken out one), and 2 of those marbles are green. Using the same principle for the third draw:

__3/12__ __2/11__ __1/10__

We need to multiply these probabilities to find out the probability of all three occurring. The product of the probabilities is 2/440, or 1/220.


Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )


Connecting to %s